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meters per seconds per second (m / s ²)
For an stoped object a increase of speed (acceleration) of 1 meter seconds per second means that after 2 seconds, object will have a speed of (1m/s x 2) = 2 m / s
the Newton's second law: Force = mass x acceleration
A force (F) in Newtons applied to an object of mass (m) in Kg causes an acceleration "a" m/s² of this object as F / m = a
This equation is implemented with some representative examples of acceleration and deceleration (accident, elevator ..) tab mass and acceleration converter included in MECAFLUX .
According to the hypothesis: "Any force acting alone is proportional to acceleration" and considering that "the weight of an object (the force applied to it) is that force is determined as the gravity acceleration the mass of an object that gives the weight of the object.
on Earth this acceleration is 9.81m / s ² at the poles and 9.78m / s ² at the equator (the effect of centrifugal force)
on the moon this acceleration is de1.62m / s ²
Representative examples of the effects of gravity (accident, elevator ..) tab mass and acceleration of converter included in MECAFLUX.
Consider an object whose trajectory is a curve
the force as to be away from the center is the centrifugal force (memotechnique: center-flee)
the force holding the object close to the center are the centripetal force (memotechnique: near center)
These two forces are equal and opposite because they are action and reaction. One can not exist without the other
with m = mass of the object, R = radius of the circular path of the object, a = centripetal acceleration, and V = velocity of the object was:
m V ² / R = Strength
a = V ² / R
In a tube tapering l 'Acceleration fluid is related to a loss of pressure. It is effect Venturi or effect Bernoulli
If the tube is narrowed between point A and point B is to:
The equation of continuity gives us a speed increase due to shrinkage as Section:
(In Section A) x (speed in A) = (in Section B) x (Speed B) = volume flow rate constant we deduce the speed at point B
(Speed B) = (in Section A) / (in Section B) x (speed in A)
Bernoulli equation links the pressure to speed:.
(pressure at point A) + (1/2 density) x (velocity at point A) ² = (pressure at point B) + (1/2 density) x (speed B) ²
replacing (speed B) by [(in Section A) / (in Section B) x (Speed A)] we have:
(pressure A) + (1/2 density) x (speed A) ² = (pressure B) + (1/2 ) x ([(Section A) / (Section B) x (speed A)]) ²
if we know the pressure drop and sections of the tubes we can deduce the velocity in A:
= pressure drop (pressure A) - (pressure B) = x 1/2masse volume (speed) ² x [(Section A ²) / (Section B ²) -1]
By knowing the speed at A we can infer the speed at B by the continuity equation already cited.
if we know the speed and sections of the tubes we can deduce the pressure drop.
Applications of these equations: flow venturi water pump systems, vacuum using compressed air stream, spray ...
 Mecaflux
comes with a converter whose functions enable the various calculations related to the acceleration.
body weight relationship acceleration deceleration / shock in the converter
related kinetic energy acceleration in the converter
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